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For the reaction, 2A(g)+B(g) rarr 2D(g...

For the reaction,
`2A(g)+B(g) rarr 2D(g)`
`DeltaU^(Θ)=-10.5 kJ` and `DeltaS^(Θ)=-44.1 JK^(-1)`
Calculate `DeltaG^(Θ)` for the reaction, and predict whether the reaction may occur spontaneously. (multiply answer with 100 and answer in KJ/mol)

Text Solution

Verified by Experts

The correct Answer is:
16
`DeltaH^(@) = DeltaU^(@) + Deltan_(g)RT`
`DeltaU^(@) = -10.5 kJ "mol"^(-1), R = 8.314 J K^(-1) mol^(-1), T = 298 K`
`Deltan_(g) = 2 - (2 + 1) = -1`
`therefore DeltaH ^(@) = - 10.5 - (1) xx 8.314 xx 10^(-3) xx 298`
` = -10.5 - 2.48`
` = -12.98 kJ "mol"^(-1)`
Now `DeltaG^(@) = DeltaH^(@) - T DeltaS^(@)`
`= -12.98 -298 xx (-44.1 xx 10^(-3))`
` = -12.98 + 13.14`
` = 0.16 kJ "mol"^(-1)`
Since `DeltaG^(@)` is positive, the reaction is not spontaneous.
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