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During a process, a system absorbs 710J ...

During a process, a system absorbs `710J` of heat and does work. The change in `DeltaU` for the process is `460J`. What is the work done by the system?

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Verified by Experts

The correct Answer is:
`-250` J

`DeltaU = q + w`
`460 = 710 + w`
`w = 460 - 710 = -250J`
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