`20.0 g` of ammonium nitrate `(NH_(4)NO_(3))` is dissolved In `125 g` of water in a coffee-cup calorimeter, the temperature falls from `296.5 K` to `286.4 K`. Find the value of `q` for the calorimeter. (Hint: heat capacity of water as the heat capacity of the calorimeter and its content)

Answer

`5.285 kJ`

Explanation

Heat capacity of water = Heat capacity of calorimeter
Heat gained by water = Heat lost by calorimeter
Heat lost by calorimeter = `C_(v) xx DeltaT`
` = m xx s xxDeltaT`
`=125 xx 4.184 xx(296.5 - 286.4)`
`= 5282.3 J`
`therefore q = 5.28 kJ`.