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At what temperature does the reduction o...

At what temperature does the reduction of lead oxide to lead by carbon becomes spontaneous?
`PbO +C rarr Pb(s) +CO(g)`
For the reacion, `DeltaH` and `DeltaS` at `25^(@)C` are `108.4 kJ mol^(-1)` and `190 J K^(-1) mol^(-1)` respectively.

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Verified by Experts

The correct Answer is:
Above 570.5 K
At equilibrium, `DeltaG = DeltaH - TDeltaS = 0`
or `DeltaH = TDeltaS`
`108.4 kJ = T (190xx 10^(-3)kJ K^(-1))`
or `T = (108.4)/(190 xx 10^(-3)) = 570.5 K`
Reaction will become spontaneous at temperature higher than 570.5 K.
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