Ammonia is prepared as
`3H_(2)(g) + N_(2)(g) to 2NH_(3)(g)`
What should be the sign of `DeltaS` for this reaction? Explain.

Explanation

To determine the sign of ΔS (change in entropy) for the reaction \( 3H_2(g) + N_2(g) \rightarrow 2NH_3(g) \), we will analyze the change in the number of gas moles and the randomness of the system.

### Step-by-Step Solution:

1. **Identify the Reactants and Products:**
- The reactants are \( 3H_2(g) \) and \( N_2(g) \).
- The product is \( 2NH_3(g) \).

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