Home
Class 11
CHEMISTRY
A swimmer coming out from a pool is cove...

A swimmer coming out from a pool is covered with a film of water weighing about 18 g. how much heat must be supplied to evaporate this water at 298 K ? Calculate the internal energy of vaperization at `100^(@)C`. `Delta_(vap)H^(Theta)` for water at 373 K = 40.66 kJ `mol^(-1)`

Text Solution

Verified by Experts

(i) 17.5 M
(ii) 71mL
Promotional Banner

Topper's Solved these Questions

  • THERMODYNAMICS

    MODERN PUBLICATION|Exercise Competition File (Integer Type Questions)|6 Videos
  • STRUCTURE OF ATOM

    MODERN PUBLICATION|Exercise Unit Practice Test|13 Videos

Similar Questions

Explore conceptually related problems

A swimmer coming out from a pool is covered with a film of water weighing about 18g. How much heat must be supplied to evaporate this water at 298 K ? Calculate the internal energy of vaporisation at 298K. Delta_("vap")H^(Ө) for water at 298K =44.01 kJ "mol"^(-1)

A swimmer coming out from a pool is covered with a film of water weighing about 80g . How much heat must be supplied to evaporate this waateer ? If latent heat of evaporation for H_(2)O is 40.79 kJ mol^(-1) at 100^(@)C .

18g of water is takento prepare the tea. Find out the internal energy of vaporisation at 100^(@) C. (Delta_(vap)H for water at 373 K 373 K is 40.66kJ mol^(-1))

Calculate the entropy change of n -hexae when 1mol of it evaporates at 341.7K (Delta_(vap)H^(Theta) = 290.0 kJ mol^(-1))

Calculate the entropy change for vaporization of 1mol of liquid water to stem at 100^(@)C , if Delta_(V)H = 40.8 kJ mol^(-1) .

The internal energy change (in J) when 90 g of water undergoes complete evaporation at 100^(@)C is ______ . (Given : Delta H_("vap") for water at 373 K = 41 kJ/ mol , R = 8.314 JK^(-1) mol^(-1) )