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Consider the following E^o values : E...

Consider the following `E^o` values :
`E^o _Fe^(3+)//FE^(2+)o = + 0.77 V`
`E_(Sn^(2+)//Sn) =- 0.14 V`
Under standard conditions the potential for reaction
`Sn(s) +2Fe^(3+) (aq) rarr 2Fe^(2+) (sq) + Sn^(2+) (aq)` is.

A

0.91 V

B

0.140 V

C

1.68 V

D

0.63 V

Text Solution

Verified by Experts

The correct Answer is:
A
`E_("cell")^@=E^@(Fe^(3+)|Fe^(2+))-E^@(Sn^(2+)|Sn)`
`=0.77-(-0.14)=+0.91V`
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