For the electrochemical cell, `M|M^(+) ||X^(-)|X`, `E_(M^(+)//M)^(@) = 0.44 V` and `E_(X//X^(-))^(@) = 0.33 V`. From this data we can deduce that :

Options

A. `M+X rarr M^(+)+X^(-)` is the spontaneous reaction
B. `M^(+)+X^(-) rarr M+X` is the spontaneous reaction
C. `E_("cell")^@=0.77V`
D. `E_("cell")^@=-0.77V`

Answer

B

Explanation

`M^(+)+e^(-)rarrM " "E^@=+0.44V " "...(i)`
`X+e^(-)rarrX^(-) " "E^@=+0.33V " "...(ii)`
Subtracting eqn. (ii) from eqn (i)
`M^(+)+X^(-) rarr M+X " "E^@=+0.11V `
Since `E^@` is positive , the reaction is spontaneous .