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The normality of '20 volume ' H(2)O(2) s...

The normality of '20 volume ' `H_(2)O_(2)` solution is

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20 volume of `H_2 O_2` solution means that 1 L of this solution will liberate 20 L of `O_2 ` at N.T.P.
`underset(68g)(2 H_2 O_2) to 2H_2 O + underset(22.4 " at N.T.P.")(O_2)`
22.4 L of `O_2 ` at N.T.P. is produced from `H_2 O_2 ` = 68 g
20 L of `O_2 ` at N.T.P. is produced from `H_2 O_2`
`=(68)/(22.4) xx 20 = 60.71 g`
Strength of `H_2 O_2` = 60.71 g/L
Gram equivalents of `H_2 O_2 = (60.71)/(17) = 3.57 `
`therefore ` Normality = `(3.57)/(1) = 3.57 `N
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