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34 g of hydrogen peroxide is present in ...

34 g of hydrogen peroxide is present in 1135 mL of solution. Volume strength of solution is

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`underset(68 g) (2H_2 O_2 ) to 2H_2 O + underset(22.4 L " at N.T.P.")(O_2)`
22.4 L of `O_2 ` at N.T.P. is produced from `H_2 O_2` = 68 g
25 L of `O_2 ` at N.T.P. is produced from `H_2 O_2`
`=(68)/(22.4) xx 25 = 76.9 g `
Strength of 25 volume `H_2 O_2 = 75.9 ` g/L
Amount of `H_2 O_2 ` present in 10 mL `= (75.9)/(1000) xx 10 `
=0.759 g.
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