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10 mL of a given solution of H(2)O(2) co...

`10 mL` of a given solution of `H_(2)O_(2)` contains `0.91 g` of `H_(2)O_(2)`. Express its strength in volume.

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`underset(68g)(2H_2 O_2) to 2H_2 O +underset(22.4 L " at N.T.P.")( O_2 )`
Amount of `H_2 O_2 ` in 1 L `=(0.91xx1000)/(10) = 91 g `
68 g of `H_2 O_2` give `O_2` at N.T.P. = 22.4 L
91 g of `H_2 O_2` will give `O_2` at N.T.P. `=(22.4)/(68)xx91`
Since 91 g of `H_2 O_2` is present in 1 L.
Volume strength = 30 volume
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