The oxide that gives `H_2 O_2` on treatment with dilute `H_2 SO_4` is

Explanation

To solve the question, we need to identify the oxide that produces hydrogen peroxide (H₂O₂) when treated with dilute sulfuric acid (H₂SO₄). Here’s a step-by-step breakdown of the solution:

### Step 1: Identify the oxide
We are looking for a specific oxide that reacts with dilute sulfuric acid to yield hydrogen peroxide. The oxide in question is barium peroxide (BaO₂).

### Step 2: Write the chemical formula
The specific form of barium peroxide we are considering is barium peroxide octahydrate, which can be represented as BaO₂·8H₂O.

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