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Commerical 11.2 volume H2 O2 solution ha...

Commerical 11.2 volume `H_2 O_2` solution has a molarity of

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To find the molarity of a commercial 11.2 volume solution of hydrogen peroxide (H₂O₂), we can follow these steps: ### Step 1: Understand the volume concept The term "11.2 volume" means that 11.2 liters of oxygen gas (O₂) is produced from 1 liter of the H₂O₂ solution when it decomposes. ### Step 2: Write the decomposition reaction The decomposition of hydrogen peroxide can be represented by the following balanced chemical equation: \[ 2 \text{H}_2\text{O}_2 \rightarrow 2 \text{H}_2\text{O} + \text{O}_2 \] ...
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The strength of H_(2)O_(2) is expressed in several ways like molarity, normality,% (w/V), volume strength, etc. The strength of "10 V" means 1 volume of H_(2)O_(2) on decomposition gives 10 volumes of oxygen at 1 atm and 273 K or 1 litre of H_(2)O_(2) gives 10 litre of O_(2) at 1 atm and 273 K The decomposition of H_(2)O_(2) is shown as under : H_(2)O_(2)(aq) to H_(2)O(l)+(1)/(2)O_(2)(g) H_(2)O_(2) can acts as oxidising as well as reducing agent. As oxidizing agent H_(2)O_(2) is converted into H_(2)O and as reducing agent H_(2)O_(2) is converted into O_(2) . For both cases its n-factor is 2. :. "Normality " " of " H_(2)O_(2) solution =2xx "molarity of" H_(2)O_(2) solution What is thepercentage strength (%w/V) of "11.2 V" H_(2)O_(2)