Which of the following compounds will show geometrical isomerism ?
(a) `H_(2)C= CBr_(2)" "(b) (H_(3))C)_(2)C= CHCH_(3)" "(c) C_(6)H_(5)CH= CHCH_(3)`
(d) `CH_(3)CH_(2)underset(CH_(3))underset(|)C=CHCH_(2)CH_(3)" "(e) H_(3)C-CH= C Cl(CH_(3))`

Explanation

To determine which of the given compounds exhibit geometrical isomerism, we need to analyze each compound based on the conditions for geometrical isomerism. Geometrical isomerism occurs in alkenes when there are different groups attached to the carbon atoms involved in the double bond, and no two groups on the same carbon can be identical.

Let's analyze each compound step-by-step:

### Step 1: Analyze Compound (a) `H2C= CBr2`
- Structure: `H2C=C(Br)2`
- On the first carbon (C1), there are two hydrogen atoms (H), and on the second carbon (C2), there are two bromine atoms (Br).
- Since both C1 and C2 have identical groups (two H's on C1 and two Br's on C2), this compound **cannot** show geometrical isomerism.
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