Write hydrocarbon radicals that can be formed as intermediates during monochlorination of 2-methylpropane ? Which of them is more stable? Give reasons.

Explanation

2- Methylpropane has two sets of equivalent hydrogens marked as a and b and therefore, gives two radicals I and II
`CH_(3)-underset(I)underset(*)overset(CH_(3))overset(|)C-CH_(3) larr overset(a)CH_(3)-overset(overset(a)CH_(3))overset(|)(""^bCH)-overset(a)CH_(3) to underset(II)(CH_(3)-overset(CH_(3))overset(|)CH-overset(*)CH_(2))`
Radical I is more stable than radical II because it is tertiary while radical II is primary. It is also stabilized due to hyperconjugation (nine structures).