An alkane `C_(8)H_(18)` is obtained as the only product on subjecting a primary alkyl halide to Wurtz reaction. On monobromination this alkane yields a single isomer of a tertiary bromide. Write the structure of alkane and the tertiary bromide.

Explanation

To solve the problem, we need to identify the alkane \( C_8H_{18} \) that can be obtained from a primary alkyl halide through the Wurtz reaction and also yields a single isomer of a tertiary bromide upon monobromination.

### Step-by-Step Solution:

1. **Understanding the Wurtz Reaction**:
The Wurtz reaction involves the coupling of two alkyl halides in the presence of sodium metal and dry ether to form a higher alkane. Since we need an alkane with the formula \( C_8H_{18} \), we can deduce that it is formed from two molecules of a primary alkyl halide.

2. **Choosing the Primary Alkyl Halide**:
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