The alkenes have `pi`-bonds which make them highly reactive. These undergo electrophilic addition reactions, addition of `HX` to unsymmetrical alkenes gives two products and follow Markovnikov rule and anti- Markovnikov rule. The addition occurs through the formation of carbocation in Markovnikov rule and free radicals in anti-Markovnikov rule. The ozonolysis reaction of alkenes helps to locate the position of double bond.
Write the major product in the following reaction:
`CH_(3)- overset(CH_(3))overset(|)(CH)-CH=CH_(2) overset(HBr)to`

Explanation

To solve the problem of adding HBr to the unsymmetrical alkene \( CH_3-CH(CH_3)-CH=CH_2 \), we will follow these steps:

### Step 1: Identify the structure of the alkene
The given alkene is \( CH_3-CH(CH_3)-CH=CH_2 \). This structure has a double bond between the last two carbon atoms, making it an unsymmetrical alkene.

### Step 2: Determine the addition reaction
When HBr is added to an unsymmetrical alkene, two possible products can be formed based on Markovnikov's rule and anti-Markovnikov's rule. However, since there is no peroxide present, we will follow Markovnikov's rule.

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