The alkenes have `pi`-bonds which make them highly reactive. These undergo electrophilic addition reactions, Addition of HX to unsymmetrical alkenes gives two products and follow Markovnikov rule and anti- Markovnikov rule. The addition occure through the formation of carbocation in Markovnikov rule and free radicals in anti-Markovnikov zule. The ozonolysis reaction of alkenes helps to locate the position of double bond.
Ozonolysis of an alkene 'A' followed by decomposition with water and a reducing agent gave a mixture of two isomers of the formula `C_(3)H_(6)O`. Give the structure of the alkene and its IUPAC name.

Explanation

To solve the problem, we need to determine the structure of the alkene 'A' based on the ozonolysis reaction that yields two isomers of the formula C₃H₆O. Here’s a step-by-step solution:

### Step 1: Understand the Ozonolysis Reaction
Ozonolysis is a reaction where ozone (O₃) reacts with alkenes to form ozonides, which can then be hydrolyzed (reacted with water) to yield carbonyl compounds (aldehydes or ketones).

### Step 2: Identify the Molecular Formula
The problem states that the ozonolysis of alkene 'A' gives two isomers with the formula C₃H₆O. This indicates that the products are likely to be either two aldehydes, two ketones, or one of each.

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