Assertion : Propene reacts with HBr in the presence of peroxides to give 1-bromopropane.
Reason : Alkenes react with HBr in the presence of peroxides according to anti Markovnikov's rule.

Options

A. Assertion and reason both are correct statements and reason is correct explanation for assertion.
B. Assertion and reason both are correct statements but reason is not correct explanation for assertion
C. Assertion is correct statement but reason is wrong statement
D. Assertion is wrong statement but reason is correct statement

Answer

To solve the question regarding the assertion and reason about the reaction of propene with HBr in the presence of peroxides, we can break down the solution into the following steps:

### Step 1: Understand the Assertion
The assertion states that propene reacts with HBr in the presence of peroxides to give 1-bromopropane.

- **Propene Structure**: Propene (C3H6) has the structure CH2=CH-CH3.
- **Reaction with HBr**: When propene reacts with HBr, we need to consider the presence of peroxides.

### Step 2: Understand the Role of Peroxides
Peroxides influence the addition of HBr to alkenes by promoting a radical mechanism rather than the typical ionic addition.

- **Radical Mechanism**: In the presence of peroxides, the addition of HBr follows a radical pathway, which leads to the formation of 1-bromopropane instead of 2-bromopropane.

### Step 3: Apply Anti-Markovnikov's Rule
The reason states that alkenes react with HBr in the presence of peroxides according to anti-Markovnikov's rule.

- **Anti-Markovnikov's Rule**: This rule states that in the addition of HX to alkenes, the hydrogen atom will attach to the carbon with the lesser number of alkyl substituents, while the halogen (Br in this case) will attach to the carbon with more alkyl substituents.

### Step 4: Analyze the Product Formation
- In propene, the double bond is between the first and second carbon (C1 and C2).
- According to anti-Markovnikov's rule, the hydrogen will add to C1 (which has fewer alkyl groups) and bromine will add to C2 (which has more alkyl groups).

### Step 5: Conclusion
- The product formed is 1-bromopropane (CH2Br-CH2-CH3).
- Therefore, both the assertion and the reason are correct.

### Final Answer
Both the assertion and the reason are correct, and the reason correctly explains the assertion. Thus, the correct option is A.

---