In the reaction,
`CH_(3)COOH underset("Heat")overset("NaOH")to X overset("NaOH, CaO")to Y`, `Y` is

Options

A. `CH_(3)CHO`
B. `CH_(4)`
C. `C_(2)H_(6)`
D. `CH_(3)COCH_(3)`

Explanation

To solve the problem, we need to analyze the given reactions step by step.

### Step 1: Identify the first reaction
The first reaction involves acetic acid (CH₃COOH) reacting with sodium hydroxide (NaOH) and heat.

**Reaction:**
\[ \text{CH}_3\text{COOH} + \text{NaOH} \xrightarrow{\text{Heat}} \text{CH}_3\text{COONa} + \text{H}_2\text{O} \]

**Product (X):** Sodium acetate (CH₃COONa) and water (H₂O) are formed.

### Step 2: Identify the second reaction
The second reaction involves sodium acetate (CH₃COONa) reacting with sodium hydroxide (NaOH) and calcium oxide (CaO). This combination is known as soda lime.

**Reaction:**
\[ \text{CH}_3\text{COONa} + \text{NaOH} + \text{CaO} \]

In this reaction, decarboxylation occurs, which means that carbon dioxide (CO₂) is released from the sodium acetate.

### Step 3: Understand decarboxylation
During decarboxylation, the acetate ion (CH₃COO⁻) loses a carbon atom in the form of carbon dioxide (CO₂). The remaining part of the acetate ion (CH₃) becomes methane (CH₄).

**Products (Y):**
1. Methane (CH₄)
2. Sodium carbonate (Na₂CO₃) is formed as a by-product.

### Conclusion
Thus, the final product Y from the reaction is **methane (CH₄)**.

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