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H(3)C-underset(CH(3))underset(|)(CH)-CH=...

`H_(3)C-underset(CH_(3))underset(|)(CH)-CH=CH_(2)+HBr to A`.
A is predominantly

A

` H_(3)C-underset(CH_(3))underset(|)CH- CH_(2)- CH_(2)Br`

B

`CH_(3)-underset(CH_(3))underset(|)overset(Br)overset(|)C- CH_(2)-CH_(3)`

C

`CH_(3)- underset(Br)underset(|)CH-underset(CH_(3))underset(|)CH-CH_(3)`

D

`CH_(3)- underset(CH_(3))underset(|)CH-underset(Br)underset(|)CH-CH_(3)`

Text Solution

Verified by Experts

The correct Answer is:
B

`H_(3)C-underset(CH_(3))underset(|)C- CH = CH_(2)+ HBr overset(+H^(+))to underset(2^(@) "Carbocation")(H_(3)C-underset(CH_(3))underset(|)CH-CH^(+)-CH_(3)) underset("Shift")overset("1,2-Hydride")to`
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