Propylene on treatment with `HBr//H_(2)O_(2)` provides

Options

A. 1-bromopropane
B. 2-bromopropane
C. 1,2-dibromopropane
D. 1-bromopropan-2-ol

Explanation

To solve the question regarding the reaction of propylene with HBr in the presence of H2O2, we will follow these steps:

### Step-by-Step Solution:

1. **Identify the Structure of Propylene**:
- Propylene (also known as propene) has the molecular formula C3H6. Its structure can be represented as:
\[ \text{CH}_2= \text{CH} - \text{CH}_3 \]
- This indicates that there is a double bond between the first two carbon atoms.

2. **Understand the Reactants**:
- The reactants are HBr (hydrobromic acid) and H2O2 (hydrogen peroxide).
- H2O2 is a peroxide, which plays a crucial role in determining the mechanism of the reaction.

3. **Apply the Anti-Markovnikov Rule**:
- In the presence of peroxides, the reaction follows the Anti-Markovnikov rule. This means that the bromine (Br) will attach to the carbon atom that has more hydrogen atoms.
- In the case of propylene, the two carbon atoms involved in the double bond are:
- Carbon 1 (C1) has 2 hydrogen atoms.
- Carbon 2 (C2) has 1 hydrogen atom.
- According to the Anti-Markovnikov rule, Br will attach to C1 because it has more hydrogen atoms.

4. **Mechanism of the Reaction**:
- The reaction proceeds via a free radical mechanism:
- **Homolytic Cleavage of H2O2**: This generates hydroxyl radicals (•OH) and bromine radicals (•Br).
- The bromine radical (•Br) then attacks the double bond of propylene.
- This results in the formation of a radical at C2, which can then react with another molecule of HBr to form the final product.

5. **Final Product Formation**:
- After the radical at C2 reacts with HBr, the final product formed is:
\[ \text{CH}_2\text{Br} - \text{CH}_2 - \text{CH}_3 \]
- This compound is known as **1-bromopropane**.

### Conclusion:
The product of the reaction of propylene with HBr in the presence of H2O2 is **1-bromopropane**.

---