What will be the main product when the following haloalkanes are treated with alcoholic KOH ?
(i) 2-bromobutane (ii) `CH_(3)CH_(2) C(CH_(3))_(2)Cl`

Explanation

To determine the main products when the given haloalkanes are treated with alcoholic KOH, we will follow a systematic approach for each compound.

### Step 1: Understanding the Reaction
Alcoholic KOH acts as a strong base and promotes elimination reactions (E2 mechanism) rather than substitution reactions. This means that it will abstract a beta hydrogen and lead to the formation of alkenes.

### Step 2: Analyze 2-bromobutane
**Structure of 2-bromobutane:**
- The structure can be represented as:
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