The position of Br in the compound in `CH_(3) CH=CHC(Br) (CH_(3))_(2)` can be classified as

Options

A. Allyl
B. Aryl
C. Vinyl
D. Secondary

Explanation

To classify the position of bromine in the compound `CH3 CH=CHC(Br)(CH3)2`, we can follow these steps:

### Step 1: Identify the Structure
First, let's write down the structure of the compound:
- The compound can be represented as:
```
CH3
|
CH3 - C - CH = CH
|
Br
```
- Here, we have a carbon chain with a double bond between the second and third carbon atoms.

### Step 2: Determine the Hybridization of the Relevant Carbons
- The carbon atom to which bromine (Br) is attached is sp³ hybridized because it is bonded to three other atoms (two CH3 groups and one carbon).
- The carbon atom next to it (the one involved in the double bond) is sp² hybridized.

### Step 3: Classify the Position of Bromine
- The classification of bromine's position can be done based on its attachment:
- **Allyl Position**: If bromine is attached to an sp³ hybridized carbon that is adjacent to an sp² hybridized carbon (which is involved in a double bond).
- **Aryl Position**: If bromine is attached to a carbon in an aromatic ring.
- **Vinyl Position**: If bromine is attached to a carbon that is part of a double bond (sp² hybridized).
- **Secondary Position**: If bromine is attached to a carbon that is bonded to two other carbons.

Since the bromine in our compound is attached to an sp³ hybridized carbon, which is adjacent to an sp² hybridized carbon, we classify this as an **allyl position**.

### Conclusion
Thus, the position of Br in the compound `CH3 CH=CHC(Br)(CH3)2` can be classified as **allyl**.

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