2-Phenyl-2-chloropropane on treatment with alc. KOH gives mainly

Options

A. 2-Phenylpropene
B. 3-Phenylpropene
C. 1-Phenylpropan-2-ol
D. 1-Phenylpropan-3-ol

Explanation

To solve the question regarding the reaction of 2-Phenyl-2-chloropropane with alcoholic KOH, we can follow these steps:

### Step 1: Understand the Reactants
2-Phenyl-2-chloropropane has the following structure:
- It consists of a propane chain (3 carbon atoms) with a phenyl group (C6H5) attached to the second carbon and a chlorine (Cl) atom also attached to the second carbon.
- The structure can be represented as:

```
Cl
|
C6H5-C-CH3
|
CH2
```

### Step 2: Identify the Role of Alcoholic KOH
Alcoholic KOH serves as a strong base. In this reaction:
- The hydroxide ion (OH-) can act as a base and will abstract a proton (H+) from a β-hydrogen (hydrogen atom on the carbon adjacent to the carbon bearing the leaving group, Cl).
- The reaction will lead to the elimination of HCl.

### Step 3: Determine the β-Hydrogens
In 2-Phenyl-2-chloropropane, the β-hydrogens are on the carbon atoms adjacent to the carbon with the Cl group. Here, both β-hydrogens are equivalent due to the symmetrical nature of the molecule.

### Step 4: Elimination Reaction
When alcoholic KOH abstracts a β-hydrogen, HCl is eliminated:
- The elimination of HCl leads to the formation of a double bond between the two adjacent carbon atoms.
- The reaction can be represented as follows:

```
Cl H
| |
C6H5-C-CH3 + KOH → C6H5-C=CH2 + HCl + KCl + H2O
|
CH2
```

### Step 5: Final Product
The major product of this elimination reaction is:
- **1-Phenylpropene**, which has the structure:

```
C6H5
|
CH=CH-CH3
```

### Conclusion
Thus, the main product formed when 2-Phenyl-2-chloropropane is treated with alcoholic KOH is **1-Phenylpropene**.

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