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H(3)C-underset(CH(3))underset(|)C=CH(2)+...

`H_(3)C-underset(CH_(3))underset(|)C=CH_(2)+HBr to A`
A (predominantly) is:

A

`CH_(3)-underset(CH_(3))underset(|)overset(Br)overset(|)C-CH_(2)CH_(3)`

B

`CH_(3)-underset(Br)underset(|)CH-underset(CH_(3))underset(|)CH-CH_(3)`

C

`CH_(3)-underset(CH_(3))underset(|)CH-underset(Br)underset(|)CH-CH_(3)`

D

`CH_(3)-underset(CH_(3))underset(|)CH-CH_(2)-CH_(2)Br`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the reaction of the given compound with HBr and determine the major product formed. The compound is 2-methylpropene (H3C-CH(CH3)=CH2), and it reacts with HBr. ### Step-by-Step Solution: 1. **Identify the Reactants:** The reactant is 2-methylpropene (H3C-CH(CH3)=CH2) and it reacts with HBr. 2. **Understand the Reaction Mechanism:** HBr dissociates into H⁺ and Br⁻. The H⁺ ion will attack the double bond (C=C) of 2-methylpropene. 3. **Formation of Carbocations:** When H⁺ adds to the double bond, two possible carbocations can form: - **Carbocation 1:** If H⁺ adds to the terminal carbon (C1), we get a secondary carbocation at C2 (CH3-CH⁺-CH2-CH3). - **Carbocation 2:** If H⁺ adds to the middle carbon (C2), we get a more stable tertiary carbocation at C1 (CH3-CH2-CH⁺-CH3). 4. **Stability of Carbocations:** The stability of carbocations increases with the number of alkyl groups attached. Tertiary carbocations are more stable than secondary ones. - Carbocation 1 (secondary) has 1 alkyl group. - Carbocation 2 (tertiary) has 3 alkyl groups. 5. **Select the More Stable Carbocation:** The tertiary carbocation is more stable due to hyperconjugation and inductive effects from the three methyl groups. Therefore, the reaction will proceed through this carbocation. 6. **Nucleophilic Attack by Br⁻:** After the formation of the more stable tertiary carbocation, the Br⁻ ion will attack this positively charged carbon, leading to the formation of the product. 7. **Final Product:** The major product formed from this reaction is 2-bromo-2-methylpropane (CH3-C(CH3)(Br)-CH3). ### Conclusion: The predominantly formed product A is 2-bromo-2-methylpropane.

To solve the problem, we need to analyze the reaction of the given compound with HBr and determine the major product formed. The compound is 2-methylpropene (H3C-CH(CH3)=CH2), and it reacts with HBr. ### Step-by-Step Solution: 1. **Identify the Reactants:** The reactant is 2-methylpropene (H3C-CH(CH3)=CH2) and it reacts with HBr. 2. **Understand the Reaction Mechanism:** ...
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