An alkyl halide with molecular formula `C_(4)H_(9)Br` is optically active. What is its structure ?

Explanation

To determine the structure of an alkyl halide with the molecular formula C₄H₉Br that is optically active, we need to follow these steps:

### Step 1: Identify the Molecular Formula
The molecular formula given is C₄H₉Br. This indicates that the compound contains 4 carbon atoms, 9 hydrogen atoms, and 1 bromine atom.

**Hint:** The number of hydrogen atoms suggests that the compound is likely to be a branched alkyl halide rather than a straight-chain alkyl halide.

### Step 2: Draw Possible Structures
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