In the given alkyl halides which one has minimum boiling point?

Options

A. `C_(2)H_(5)F`
B. `C_(2)H_(5)I`
C. `C_(2)H_(5)Cl`
D. `C_(2)H_(5)Br`

Answer

To determine which alkyl halide has the minimum boiling point among the given options, we can follow these steps:

### Step 1: Identify the Alkyl Halides
List the alkyl halides provided in the question. For example, let's assume the alkyl halides are:
1. CH3Cl (Methyl chloride)
2. CH3Br (Methyl bromide)
3. CH3I (Methyl iodide)
4. C2H5Cl (Ethyl chloride)

### Step 2: Understand the Factors Affecting Boiling Point
The boiling point of a compound is influenced by the molecular weight and the type of intermolecular forces present. Generally, as molecular weight increases, the boiling point also increases due to stronger London dispersion forces.

### Step 3: Compare Molecular Weights
Calculate or identify the molecular weights of each alkyl halide:
- CH3Cl: 12 (C) + 3(1) (H) + 35.5 (Cl) = 50.5 g/mol
- CH3Br: 12 (C) + 3(1) (H) + 80 (Br) = 95 g/mol
- CH3I: 12 (C) + 3(1) (H) + 127 (I) = 142 g/mol
- C2H5Cl: 2(12) (C) + 5(1) (H) + 35.5 (Cl) = 60.5 g/mol

### Step 4: Arrange by Molecular Weight
Now, arrange the alkyl halides in order of increasing molecular weight:
1. CH3Cl: 50.5 g/mol
2. C2H5Cl: 60.5 g/mol
3. CH3Br: 95 g/mol
4. CH3I: 142 g/mol

### Step 5: Determine the Minimum Boiling Point
Since boiling point is generally higher with increasing molecular weight, the alkyl halide with the lowest molecular weight will have the minimum boiling point. From our arrangement, CH3Cl (Methyl chloride) has the lowest molecular weight.

### Conclusion
Therefore, the alkyl halide with the minimum boiling point is **CH3Cl (Methyl chloride)**.

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