Ethyl bromide reacts with alcoholic solution of KCN and AgCN to give different products having same molecular formula. These further react with other reagents to form different products.
Name the different products formed by reaction of ethyl bromide with KCN and AgCN.

Explanation

To solve the problem, we need to analyze the reactions of ethyl bromide (C2H5Br) with two different reagents: alcoholic KCN and AgCN. Each of these reactions will yield different products, despite having the same molecular formula.

### Step 1: Reaction of Ethyl Bromide with KCN
1. **Starting Material**: Ethyl bromide (C2H5Br) is a primary alkyl halide.
2. **Reagent**: KCN (potassium cyanide) in alcoholic solution.
3. **Mechanism**: The cyanide ion (CN⁻) acts as a nucleophile and attacks the carbon atom attached to the bromine atom. This results in the displacement of bromide ion (Br⁻).
4. **Product Formation**: The product formed is ethyl cyanide (C2H5CN).

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