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H(3)C-underset(CH(3))underset(|)(CH)-CH=...

`H_(3)C-underset(CH_(3))underset(|)(CH)-CH=CH_(2)+HBr to A`.
A is predominantly

A

`CH_(3)-underset(CH_(3))underset(|)overset(Br)overset(|)C-CH_(2)CH_(3)`

B

`CH_(3)-underset(Br)underset(|)CH-underset(CH_(3))underset(|)CH-CH_(3)`

C

`CH_(3)-underset(CH_(3))underset(|)CH-underset(Br)underset(|)CH-CH_(3)`

D

`CH_(3)-underset(CH_(3))underset(|)CH-CH_(2)-CH_(2)Br`

Text Solution

Verified by Experts

The correct Answer is:
A
`CH_(3)underset(CH_(3))underset(|)CH-CH=CH_(2)+HBr overset(-Br^(-))to underset((2^(@) -"Carbocation"))(CH_(3)-underset(CH_(3))underset(|)CH-overset(+)CH-CH_(3)) underset("shift")overset("1,2-hydride")to underset(underset("(more stable)")(3^(@) "Carbocation"))(CH_(3)-underset(CH_(3))underset(|)overset(+)C-CH_(2)-CH_(3)) overset(+Br^(-))to CH_(3)-underset(CH_(3))underset(|)overset(Br)overset(|)C-CH_(2)-CH_(3)`
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