Arrange the following in the increasing order of their `pK_(b)` values.
`C_(6)H_(5)NH_(2), C_(2)H_(5)NH_(2), C_(6)H_(5)NHCH_(3)`

Explanation

To solve the problem of arranging the compounds \( C_6H_5NH_2 \) (aniline), \( C_2H_5NH_2 \) (ethylamine), and \( C_6H_5NHCH_3 \) (N-methyl aniline) in increasing order of their \( pK_b \) values, we need to analyze the basicity of each compound. The \( pK_b \) value is inversely related to the basic strength; that is, the stronger the base, the lower the \( pK_b \) value.

### Step-by-Step Solution:

1. **Identify the Compounds**:
- \( C_6H_5NH_2 \) is aniline.
- \( C_2H_5NH_2 \) is ethylamine.
- \( C_6H_5NHCH_3 \) is N-methyl aniline.
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