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In Schotten-Baumann reaction, aniline is...

In Schotten-Baumann reaction, aniline is heated with .........

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### Step-by-Step Solution: 1. **Identify the Reactants**: The Schotten-Baumann reaction involves aniline (C6H5NH2) and benzoyl chloride (C6H5COCl). 2. **Understanding the Reaction Mechanism**: In this reaction, the nitrogen atom in aniline has a lone pair of electrons, which makes it a nucleophile. Benzoyl chloride contains a carbonyl group (C=O) and a chlorine atom (Cl), where the carbon atom is electrophilic due to the electron-withdrawing effect of the chlorine. 3. **Nucleophilic Attack**: The lone pair of electrons on the nitrogen atom of aniline attacks the electrophilic carbon atom of benzoyl chloride. This forms a tetrahedral intermediate. ...
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Knowledge Check

  • Schotten Baumann reaction is

    A
    `"Phenol + Benzoyl chloride" overset(NaOH)rarr "Phenyl banzoate"`
    B
    `"Sodium phenate + methyl iodide" overset(-HCl)rarr "Anisole"`
    C
    `"Phenol + Chloroform" overset(NaOH)rarr "Salicyladehyde"`
    D
    `"Benzene diazonium chloride + Phenol" rarr beta-"Hydroxyazobenzene"`

  • Schotten Baumann reaction is

    A
    Phenol `+` Benzoyl chloride `overset(NaOH)rarr` Phenyl benzoate
    B
    Sodium phenate `+` methyl iodide `overset(-HCl)rarr` Anisole
    C
    Phenol `+` chloroform `overset(NaOH)rarr` salicyladehyde
    D
    Benzenediazonium chloride `+` phenol `rarr p-` Hydroxyazobenzene

  • The schotten-Baumann reaction is:

    A
    `ROH+PhCOCI` `overset (NaOH) rarr` `ROCOPh`
    B
    `ROH_MeCOCI` `overset (Py) rarr` `ROCOMe`
    C
    `ROH+PhCH_(2)COCI` `overset (NaOH) rarr` `ROCOCH_(2)Ph`
    D
    `RNH_(2)+MeCOCI` `overset (Py) rarr` `RNHCOMe`