In the hofmann-bromamide degradation reaction, the number of moles of NaOH and `Br_(2)` used per mole of amine produced are

Options

A. one mole of NaOH and one mole of `Br_(2)`
B. four moles of NaOH and two moles of `Br_(2)`
C. two moles of NaOH and two moles of `Br_(2)`
D. four moles of NaOH and one mole of `Br_(2)`

Answer

D

Explanation

`RCONH_(2) + 4NaOH + Br_(2) to RNH_(2) + Na_(2)CO_(3) + 2NaBr + 2H_(2)O` i.e,
4 mole of NaOH and 1 mole of `Br_(2)`.