Cyclohexylamine and aniline can be distinguished by

Options

A. Hinsberg's test
B. Carbylamine test
C. Bromine test
D. Beilstein's test

Explanation

To distinguish between cyclohexylamine and aniline, we can use the Bromine test. Here’s a step-by-step explanation of how this works:

### Step 1: Understand the Structures
- **Cyclohexylamine**: This is a six-membered carbon ring (cyclohexane) with an amino group (-NH2) attached.
- **Aniline**: This is a benzene ring with an amino group (-NH2) attached.

### Step 2: Perform the Bromine Test
- When bromine (Br2) is added to aniline, the amino group (-NH2) is activated due to resonance with the benzene ring. This leads to the substitution of bromine atoms at the ortho and para positions of the benzene ring.
- The reaction will produce a white precipitate of 2,4,6-tribromoaniline.

### Step 3: Observe the Reaction with Cyclohexylamine
- Cyclohexylamine, on the other hand, does not have a benzene ring. When bromine is added to cyclohexylamine, there is no significant reaction, and thus no white precipitate is formed.

### Step 4: Conclusion
- The formation of a white precipitate indicates the presence of aniline, while the lack of reaction indicates cyclohexylamine. Therefore, the Bromine test can effectively distinguish between the two compounds.

### Final Answer
The correct method to distinguish cyclohexylamine from aniline is the **Bromine test** (Option C).

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