Home
Class 11
BIOLOGY
Roots obtain oxgyen from air soil for re...

Roots obtain oxgyen from air soil for respiration , In the absence or deficiency of `O_(2)` , root growth is restricted or completely stopped. How do the plants growing in marsh lands or swamps obtain their `O_(2)` required for root respiration ?

Text Solution

Verified by Experts

Plants like Rhizophora, which grow in marshy or swamp area bear pneumatophores or respiratory roots. These roots come out of soil, grow vertically and bear respiratory pores (pneumathodes) for respiration.
Promotional Banner

Topper's Solved these Questions

  • MORPHOLOGY OF FLOWERING PLANTS

    MODERN PUBLICATION|Exercise NCERT FILE ( NCERT EXEMPLAR PROBLEM (C. SHORT ANSWER TYPE QUESTIONS) )|14 Videos
  • MORPHOLOGY OF FLOWERING PLANTS

    MODERN PUBLICATION|Exercise NCERT FILE ( NCERT EXEMPLAR PROBLEM (D. LONG ANSWER TYPE QUESTIONS) )|7 Videos
  • MORPHOLOGY OF FLOWERING PLANTS

    MODERN PUBLICATION|Exercise NCERT FILE ( NCERT EXEMPLAR PROBLEM (A. MULTIPLE CHOICE QUESTIONS) )|9 Videos
  • MINERAL NUTRITION

    MODERN PUBLICATION|Exercise CHAPTER PRACTICE TEST|16 Videos
  • NEURAL CONTROL AND COORDINATION

    MODERN PUBLICATION|Exercise Chapter Practice Test|11 Videos

Similar Questions

Explore conceptually related problems

Respiration requires O_(2) . How did the first cells on the earth magage to survive in an atmosphare that lacked O_(2) ?

Statement 1: To maintain soil fertility, it is essential to prevent desertification and deforestation. Statement 2: Roots of plants grasp soil well and prevent removal of top soil by air, water, etc.

The trajectory of a projectile is given by y=x tantheta-(1)/(2)(gx^(2))/(u^(2)cos^(2)theta) . This equation can be used for calculating various phenomen such as finding the minimum velocity required to make a stone reach a certain point maximum range for a given projection velocity and the angle of projection required for maximum range. The range of a particle thrown from a tower is define as the distance the root of the tower and the point of landing. From a certain tower of unknown height it is found that the maximum range at a certain projection velocity is obtained for a projection angle of 30^(@) and this range is 10sqrt(3)m . The projection velocity must be

The trajectory of a projectile is given by y=x tantheta-(1)/(2)(gx^(2))/(u^(2)cos^(2)theta) . This equation can be used for calculating various phenomen such as finding the minimum velocity required to make a stone reach a certain point maximum range for a given projection velocity and the angle of projection required for maximum range. The range of a particle thrown from a tower is define as the distance the root of the tower and the point of landing. In the previous problem, what should be the corresponding projection angle.

The trajectory of a projectile is given by y=x tantheta-(1)/(2)(gx^(2))/(u^(2)cos^(2)theta) . This equation can be used for calculating various phenomen such as finding the minimum velocity required to make a stone reach a certain point maximum range for a given projection velocity and the angle of projection required for maximum range. The range of a particle thrown from a tower is define as the distance the root of the tower and the point of landing. A tower is at a distance of 5m from a man who can throw a stone with a maximum speed of 10m//s . What is the maximum height that the man can hit on this tower.

MODERN PUBLICATION-MORPHOLOGY OF FLOWERING PLANTS -NCERT FILE ( NCERT EXEMPLAR PROBLEM (B. VERY SHORT ANSWER TYPE QUESTIONS) )
  1. Roots obtain oxgyen from air soil for respiration , In the absence or ...

    Text Solution

    |

  2. Write floral formula for a flower which is bisexual, actinomorphic sep...

    Text Solution

    |

  3. In Opuntia, the stem is modified into a flattened green structure of p...

    Text Solution

    |

  4. In swampy areas like the sunderbans in West Bengal, plants bear specia...

    Text Solution

    |

  5. In aquatic plants like Pistia and Eichhornia, leaves and roots are fou...

    Text Solution

    |

  6. Reticulate and parallel venation are the characteristic of …… and …….....

    Text Solution

    |

  7. Which parts of ginger and onion are edible?

    Text Solution

    |

  8. In epigynous flower , ovary is situated below the ……… .

    Text Solution

    |

  9. Add the missing floral organ of the given floral floral formula of Fab...

    Text Solution

    |

  10. Name the body part modified for food storage in the Carrot

    Text Solution

    |

  11. Name the body part modified for food storage in the Colocasia

    Text Solution

    |

  12. Name the body part modified for food storage in the Sweet potato

    Text Solution

    |

  13. Name the body part modified for food storage in the Asparagus

    Text Solution

    |

  14. Name the body part modified for food storage in the Radish

    Text Solution

    |

  15. Name the body part modified for food storage in the Potato

    Text Solution

    |

  16. Name the body part modified for food storage in the Dahlia

    Text Solution

    |

  17. Name the body part modified for food storage in the Turmeric

    Text Solution

    |

  18. Name the body part modified for food storage in the Gladiolus

    Text Solution

    |

  19. Name the body part modified for food storage in the Ginger

    Text Solution

    |

  20. Name the body part modified for food storage in the Portulaca

    Text Solution

    |