A normal man marries a woman who is carrier of colour blindness.What will be the phenotype of the children born to them?Depict the phenotype through a cross.

Explanation

To determine the phenotypes of the children born to a normal man and a woman who is a carrier of color blindness, we can follow these steps:

### Step 1: Understand the Genetics of Color Blindness
Color blindness is an X-linked recessive disorder. This means that the gene responsible for color blindness is located on the X chromosome, and the condition is expressed in males (XY) if they inherit the affected X chromosome, while females (XX) can be carriers if they have one affected X chromosome and one normal X chromosome.

### Step 2: Determine the Genotypes of the Parents
- The normal man has a genotype of **XY** (where X is normal).
- The woman who is a carrier has a genotype of **XXᶜ** (where Xᶜ is the affected X chromosome for color blindness and X is the normal X chromosome).
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