" Find the value of "(sin(alpha+beta))/(sin(alpha-beta))," given that "tan alpha=2tan beta

Find the value of (sin (alpha + beta))/(sin (alpha - beta)), "given that" tan alpha = 2 tan beta.

Show that (sin (alpha + beta))/( sin (alpha + beta)) = 2, given that tan alpha = 2 tan beta.

(sin(alpha+beta))/(sin(alpha-beta))=(a+b)/(a-b) then (tan alpha)/(tan beta)=

If sin alpha=(15)/(17) and cos beta=(12)/(13) find the values of sin(alpha+beta),cos(alpha-beta) and tan(alpha+beta)

Find the value of sin (alpha - beta), cos (alpha -beta) and tan (alpha - beta), given sin alpha = (8)/(17) , tan beta = (5)/(12), alpha and beta in Quadrant I.

Find the value of sin (alpha + beta) , cos (alpha + beta) , and tan (alpha + beta), given sin alpha = (3)/(5) , cos beta = (5)/(13), alpha and beta in Quadrant I.

If alpha and beta are acute angles and sin alpha = (3)/(5) , sin beta = (8)/( 17), find the values of sin ( alpha + beta), cos (alpha pm beta), and tan ( alpha pm beta).

If sin(alpha+beta)=(4)/(5), sin(alpha-beta)=(5)/(13) , find the value of tan 2alpha :

sin alpha sin beta-cos alpha cos beta=1 then show that tan alpha+tan beta=0

If sin(alpha+beta)=1,sin(alpha-beta)=(1)/(2) then tan(alpha+2 beta)tan(2 alpha+beta)=