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[24." The frequency of radiation emitted...

[24." The frequency of radiation emitted when "],[" the electron falls from "n=4" to "n=1" in a "],[" hydrogen atom will be (Given ionisation "],[" energy of "H=2.18times10^(-18)" ] atom "^(-1)" and "],[h=6.625times10^(-34)" Js) "quad [" CBSE AIPMT "2004}],[[" (a) "1.54times10^(15)s^(-1)," (b) "1.03times10^(15)s^(-1)],[" (c) "3,08times10^(15)s^(-1)," (d) "2.00times10^(15)s^(-1)]]

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The frequency of radiations , emitted when the electron falls , from n=4 to n=1 in a hydrogen , atom

The frequency of radiation emitted when the electron falls from n=4 to n=1 in a hydrogen atom will be (given ionisation energy of H=2.18xx10^(18)J"atom"^(-1) and h=6.625xx10^(-25)Js )

The frequency of radiation emitte when the electron falls from 'n=4' to 'n=1' in 'a' hydrogen atom will be (given ionization energy of 'H=2.1810^(-18) J' atom '^(-1)' and 'h=' '6.625 xx 10^(-34)' Js)

The frequency of radiation emiited when the electron falls n =4 to n=1 in a hydrogen atom will be ( given ionization energy of H= 2.18 xx 10 ^(-18)J "atom "^(-1) and h= 6.625 xx 10 ^(-34)Js)

The frequency of radiation emiited when the electron falls n =4 to n=1 in a hydrogen atom will be ( given ionization energy of H= 2.18 xx 10 ^(-18)J "atom "^(-1) and h= 6.625 xx 10 ^(-34)Js)

Calculate the energy and frequency of the radiation emitted when an electron jumps from n=3 to n=2 ina hydrogen atom.