[" 6.A force "2hat i+hat j-hat k" newton acts on a body which is intially at rest.At the end of "20" seconds,"],[" the velocity of the body is "4hat i+2hat j-2hat kms^(-1)." What is the mass of the body? "]

A force (2hat I + hat j - hat k)N acts on a body which is initially at rest. At the end of 20 sec the velocity of the body is (4 hat i + 2 hat j – 2 hat k) ms^(-1) ,then mass of the body is

A force of (2.6 hat(i) + 1.6 hat(j)) N acts on a body of mass 2 kg. If the velocity of the body at time, t = 0 is (3.6 hat(i) - 4.8 hat(j)) ms^(-1) , the time at which the body will just have a velocity along x-axis only is

A point on the line hat r=2hat i+3hat j+4hat k+t(hat i+hat j+hat k) is

If vec F =2 hat i + 3hat j +4hat k acts on a body and displaces it by vec S =3 hat i + 2hat j + 5 hat k , then the work done by the force is

A force (3 hat(i)+4 hat(j)) acts on a body and displaces it by (3 hat(i)+4 hat(j))m . The work done by the force is

The , perpendicular vector on both of (3hat i +hat j + 2hat k) and (2hat i -2hat j +4hat k) is:

A force of 6 hat i+ 7 hat j newton makes a body move on a rough loane with a velocity of (4 hat j = 3 hat k) ms^(-1) . Calculate the power in watt.

Work done by a force F on a body is W = F .s, where s is the displacement of body. Given that under a force F = (2 hat i +3 hat j +4 hat k) N a body is displaced from position vector r_1 = (2 hat i +3 hat j + hat k) m to the position vector r_2 = (hat i +hat j+ hat k) m. Find the work done by this force.