What is the change in entropy when `2.5` mole of water is heated from `27^(@)C` to `87^(@)C`?
Assume that the heat capacity is constant `(C_(p))_(m)(H_(2)O)=4.2J//g=k,ln(1.2)=0.18)`

What is the change in entropy when 2.5 mole of water is heated from 27^(@)C to 87^(@)C ? Assume that the heat capacity is constant (C_(p))_(m)(H_(2)O)=4.2J//gK, ln(1.2)=0.18)

A sample of 100 g water is slowly heated from 27^((0))C to 87^((0))C Calculate the water =4200 J kg ^(-1)K^(-1) .

Calculate the change in internal energy when 5g of air is heated from 0^(@) to 4^(@)C . The specific heat of air at constant volume is 0.172 cal g^(-1) .^(@)C^(-1) . a) 28.8 J b) 14.4 J c) 7.2 J d) 3.51 J

A sample of 100 g water is slowly heated from 27^(o)C to 87^(o)C . Calculate the change in the entropy of the water. specific heat capacity of water =4200 j/kg k .

A sample of 100 g water is slowly heated from 27^(o)C to 87^(o)C . Calculate the change in the entropy of the water. specific heat capacity of water =4200 j/kg k .

A sample of 100 g water is slowly heated from 27^@C to 87^@C . Calculate the change in the entropy of the water specific heat capacity of water =4200(J)/(kg-K)

Calculate the entropy change when 1 kg of water is heated from 27^(@)C to 200^(@)C forming supper heated steam under constant pressure. Given specific heat of water = 4180 J Kg^(-1)K^(-1) and specific heat of steam = 1670 + 0.49 J kg^(-1)K^(-1) and latent heat of vaporisation =23 xx 10^(5) J kg^(-1) .

At constant pressure 200g of water is heated from 10^(@)C to 20^(@)C .Thus,increase in entropy is (molar heat capacity of water at constant pressure is 75.3JK^(-1)mol^(-1) )

A sample of 100 gm of water is slowly heated from 27^(@)C to 87^(@)C . Calculate the change in the entropy of water. Specific heat capacity of water = 4200 J cdot kg^(-1) cdot K^(-1)