The line `(x)/(1)=(y)/(2)=(z)/(2)`and plane `2x-y+z=2` cut at a point A .The distance of point A from origin is:

If the line (x-1)/(2)=(y+1)/(3)=(z-2)/(4) meets the plane, x+2y+3z=15 at a point P, then the distance of P from the origin is

The line (x-3)/1=(y-4)/2=(z-5)/2 cuts the plane x+y+z=17 at

Distance of the point of intersection of the line (x-3)/(1)=(y-4)/(2)=(z-5)/(2)and plane x+y+z=2 from the point (3,4,5) is

The line (x-1)/2=(y-2)/3=(z-3)/4 meets the plane 2x+3y-z=14 in the point

If the projection of the line (x)/(2)=(y-1)/(2)=(z-1)/(1) on a plane P is (x)/(1)=(y-1)/(1)=(z-1)/(-1) Then the distance of plane P from origin is

Consider a plane x+2y+3z=15 and a line (x-1)/(2)=(y+1)/(3)=(z-2)/(4) then find the distance of origin from point of intersection of line and plane.