The are of the triangel inscribed in the parabola `y^(2)=4x` the ordinates of whose vertices are 1, 2 and 4 square units, is

Area bounded by the parabola y^(2)=2x and the ordinates x=1, x=4 is

The length of the side of an equilateral triangle inscribed in the parabola,y^(2)=4x so that one of its angular point is at the vertex is:

" The point of intersection of the tangents at the points on the parabola " y^(2)=4x " whose ordinates are " 4 " and " 6 " is

If y_(1),y_(2),y_(3) be the ordinates of a vertices of the triangle inscribed in a parabola y^(2)=4ax then show that the area of the triangle is (1)/(8a)|(y_(1)-y_(2))(y_(2)-y_(3))(y_(3)-y_(1))|

If an equilateral triangle is inscribed in a parabola y^(2)=12x with one of the vertices being at the vertex of the parabola then its height

If an equilateral triangle is inscribed in a parabola y^(2)=12x with one of the vertices being at the vertex of the parabola then its height is

The co-ordinates of a point on the parabola y^(2)=8x whose ordinate is twice of abscissa, is :

If 2,4,8 are the ordinates of the vertices of a triangle inscribed in the parabola y^(2)=8x ,then area of triangle is

An equilateral triangle is inscribed in the parabola y^(2)=4ax whose vertex is at of the parabola.Find the length of its side.