Find the sum of ( n + 1 ) terms of the following series `2 C_ 0 − 3 C_ 1 + 4 C_ 2 − 5 C_ 3 + ... ...`

If C_(r) stands for nC_(r), then the sum of first (n+1) terms of the series aC_(0)-(a+d)C_(1)+(a+2d)C_(2)-(a+3d)C_(3)+...... is

The sum to (n+1) terms of the series (C_(0))/(2)-(C_(1))/(3)+(C_(2))/(4)-(C_(3))/(5)+......=

Find the nth term and the sum of n terms of the series 1.2.4+2.3.5+3.4.6+....

If (1+x)^n=C_0+C_1x+C_2x^2+...+C_nx^n , find the sum of the following series : aC_1+(a+d)C_2+(a+2d)C_3+...+(a+bar(n-1)d)C_n

The sum of :3.^(n)C_(0)-8.. upto (n+1) terms is (n>=2):

Find the sum of the series quad 15C_(0)+^(15)C_(1)+^(15)C_(2)++^(15)C_(7)

The sum of the following series upto'n' terms is given by S=^(n)C_(0)+2.^(n)C_(1)+4^(n)C_(2)+7.^(n)C_(3)+11.^(n)C_(4)+