Range of `sec^(-1)[1+cos^(2)x]` is `{sec^(-1)a,sec^(-1)b}` then a+b =? (where [.] is GIF)

Range of sec^(-1)x is

Range of f(x)=sin^(-1)x+sec^(-1)x is

Is sec^(-1) (-x) = pi - sec^(-1) x , |x| ge 1 ?

sec(cos ec^(-1)x) is equal to : (where |x|>=1)

sec^(-1)x+cos ec^(-1)x=(pi)/(2)

(sec 2A+1 ) sec ^(2) A=

solve the following equation sec^(-1).(x)/(a) - sec^(-1).(x)/(b) = sec^(-1) b - sec^(-1) a, a ge 1, b ge 1, a!= b

cos x+sec x=2rArr cos^(m)x+sec^(m)x=1-11

Solve,(sec^(-1))(x)/(a)-(sec^(-1))(x)/(b)=sec^(-1)b-sec^(-1)a