If 0 lt x lt 1000 and [(x)/(2)]+[(x)/(3)...

If `0 lt x lt 1000` and `[(x)/(2)]+[(x)/(3)]+[(x)/(5)]=(31)/(30)x,` where `[x]` is the greatest integer less than or equal to `x` ,the number of possible values of `x` is

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