A body is acted upon by a force `vec(F)=-hati+2hatj+3hatk`. The work done by the force in displacing it from (0,0,0) to (0,0,4m) will be -

A force F_(y)=(3x+2)" N" is acting on a body. The work done by this force if it tends to displace the body from x = 0 m to x = 4 m will be

A force F_(y)=(3x+2)" N" is acting on a body. The work done by this force if it tends to displace the body from x = 0 m to x = 4 m will be

A force of (3 hati + 4 hatj) Newton acts on a body and it by (3 hati + 4 hatj)m . The work done by the force is

A particle is acted upon by constant forces vecF=-2hati+3hatj+4hatk and vecF_(2)=- hati+2hatj-3hatk is distanced from the point A (2,1,0,) to the point B(-3,-4,2) Find the work done by forces.

Work done by a force vecF =(hati+2hatj+3hatk) N acting on a particle in displacing it from the point vecr_2=hati-hatj+2hatk to the point vecr_1=hati+hatj+hatk is

A particle is acted upon by constant forces 4hati +hatj - 3hatk and 3hati + hatj -hatk which displace it from a point hati + 2hatj + 3hatk to the point 5hati + 4hatj + hatk . The work done in standard units by the forces is given by:

A body is displaced from (0,0) to (1 m, 1m) along the path x = y by a force F=(x^(2) hatj + y hati)N . The work done by this force will be

A body is displaced from (0,0) to (1 m, 1m) along the path x = y by a force F=(x^(2) hatj + y hati)N . The work done by this force will be