If `x=3t " and " y=(2t)/3-1`, then find the value of t for which x = 3y.

If x=2t and y=(2t-1)/(3) , then for what value of t, x=y is correct?

Let x=x(t) and y=y(t) be solutions of the differential equations (dx)/(dt)+ax=0 and (dy)/(dt)+by=0] , respectively, a,b in R .Given that x(0)=2,y(0)=1 and 3y(1)=2x(1) ,the value of "t" ,for which, [x(t)=y(t) ,is :

If t is real and lambda = (t^2-3t+4)/(t^2+3t+4) then find number of the solution of the systems of equation 3x-y+4z =0,x+2y-3z=-2.6x+5y+lambda z=-3 for a particular value of lambda .

If x = a sin 2 t(1+cos 2t) and y = b cos 2t(1-cos 2t), find: the value of dy/dx at t = pi/4 and t = pi/3

Find dy/dx, x=acos^3t,y=asin^3t, find the value at pi/4

If x=tan^(-1)t, and y=t^(3), find (dy)/(dx)

If t is a parameter and x=t^(2)+2t, y=t^(3)-3t , then the value of (d^(2)y)/(dx^(2)) at t=1 is -

If t is real and lambda=(t^(2)-3t+4)/(t^(2)+3t+4) then find number of the solution of the systems of equation 3x-y+4z=0,x+2y-3z=-2.6x+5y+lambda z= for a particular value of lambda .

If x^(2)+y^(2)=t+(1)/(t) and x^(4)+y^(4)=t^(2)+(1)/(t^(2)) , then the value of -x^(3)y(dy)/(dx) is -