System shown in figure is in equilibrium, find the magnitude of net change in the string tension between two masses just after, when one of the springs in cut, Mass of both the blocks is same and equal to m spring constant of both springs is k.
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System shown in fig is in equilibrium and at rest. The spring and string are massless now the string is cut. The acceleration of mass 2m and m just after the string is cut will be:

System shown in fig is in equilibrium and at rest. The spring and string are massless now the string is cut. The acceleration of mass 2m and m just after the string is cut will be:

System shown in fig is in equilibrium and at rest. The spring and string are massless now the string is cut. The acceleration of mass 2m and m just after the string is cut will be:

System shown in figure is equilibrium in vertical plane. Consider the string and spring to be massless. Both the blocks have same mass 'm' . If the string is cut, then just after cutting it :

System shown in figure is equilibrium in vertical plane. Consider the string and spring to be massless. Both the blocks have same mass 'm' . If the string is cut, then just after cutting it :

The system shown in the figure is in equilibrium at rest. The spring and string are massless Now the string is cut. Find the acceleration of the blocks just after the string is cut.

The system shown in the figure is in equilibrium at rest. The spring and string are massless Now the string is cut. Find the acceleration of the blocks just after the string is cut.

A block of mass 1kg is dropped on a spring - mass system as shown in the figure. The block traves 100 meters in the air before strinking the 3 kg mass. Calculate maximum compression in the spring, if both the blocks move together after the collision. Spring constant of the string k=1.25xx10^(6) .