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" 3."(d)/(dx)(sec x)quad " isses "...

" 3."(d)/(dx)(sec x)quad " isses "

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(d)/(dx)(sec^(-1)x)

(d)/(dx)[sec(2x^(2))]

(d)/(dx)[log(sec x+tan x)]=

(d)/(dx)[sqrt((sec x-1)/(sec x+1))]=

(d)/(dx)[sec(tan^(-1)x)]=

(d)/(dx)(sec^(2)xcsc^(2)x)=

(d)/(dx) {Sec^(-1) e ^(x) }=

(d)/(dx) tan^(-1) (sec x - tan x) - Find

(d)/(dx)(sec^(2)x*csc^(2)x)=