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If cos e c^(-1)(cos e cx)a n dcos e c(co...

If `cos e c^(-1)(cos e cx)a n dcos e c(cos e c^(-1)x)` are equal functions, then the maximum range of value of `x` is `[-pi/2,-1]uu[1,pi/2]` (b) `[-pi/2,0]uu[0,pi/2]` `(-oo,-1)uu[1,oo]` (d) `[-1,0]uu[0,1]`

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If cos ec^(-1)(cos ecx) and cos ec(cos ec^(-1)x) are equal functions,then the maximum range of value of x is (a) [-(pi)/(2),-1]uu[1,(pi)/(2)] (b) [-(pi)/(2),0]uu[0,(pi)/(2)](c)(-oo,-1)uu[1,oo] (d) [-1,0]uu[0,1]

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If y=tan^(-1)x+tan^(-1)(1/x)+sec^(-1)x , then y lies in the interval (a) [pi/2,pi)uu[pi,(3pi)/2) (b) [pi/2,(3pi)/2] (c)(0,pi) (d) [0,pi/2)uu[pi/2,pi)

For x^(2)-(a+3)|x|+4=0 to have real solution,the range of a is (-oo,-7]uu[1,oo) b.(-3,oo) c.(-oo,-7)d*[1,oo)

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Range of f(x)=(1)/(1-2cos x) is (1)[(1)/(3),1] (2) [-1,(1)/(3)](3)(-oo,-1]uu[(1)/(3),oo)(4)[-(1)/(3),1]

Complete solution set of the inequation (x^(2)-1)(x^(2)-6x+8)>=0 is x in[-1,1]uu[2,4]x in(-oo,-1)uu[1,2]uu[4,oo]x in[-1,2]uu[4,oo](d) none of these

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The solution set of the equation [x]^(2) +[x+1]-3=0 , where [*] represents greatest integer function is (A) [-1,0)uu[1,2) (B) [-2,-1) uu[1,2) (C) [1,2) (D) [-3,-2)uu[2,3)

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